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README.md
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# Sudoku Solver (Prolog)
# INTRODUCTION
Run by using the command
A **Latin square** of order _n_ is an _n × n_ array in which each cell contains a single symbol
problem(1,Rows), sudoku(Rows), maplist(portray_clause, Rows).
from a set _S_ with _n_ elements, such that each symbol occurs exactly once in each row
and exactly once in each column.
_Example:_
![](sudoku-screenshots/latin.png)
a Latin square of order 3
A **Sudoku Latin square** is a Latin square of order 9 on the symbol set {1,..., 9} that
is partitioned into 3 _×_ 3 squares, and each square contains all symbols.
![](sudoku-screenshots/1.png)
This can also be represented as
![](sudoku-screenshots/2.png)
This can be further represented as a list of variables:
![](sudoku-screenshots/3.png)
And we represent the whole sudoku latin square as a list of lists.
![](sudoku-screenshots/4.png)
So, in total, we have a list of rows.
More problems-
# CLP(FD) CONSTRAINTS
puzzle(1, [[_,4,_,9,_,_,_,5,_],
[2,_,_,_,_,_,_,4,_],
[1,9,_,_,8,_,7,_,_],
[5,_,_,_,_,_,1,_,_],
[_,_,7,_,6,_,_,_,3],
[_,_,_,_,3,_,8,9,_],
[_,8,_,3,4,_,_,6,_],
[3,_,_,2,_,8,_,_,_],
[_,_,_,_,_,_,_,_,_]]).
The library clpfd or Constraint Logic Programming over Finite Domains contains a lot
puzzle(2, [[_,_,9,5,_,_,_,3,7],
[1,3,7,9,_,_,_,5,2],
[2,_,_,_,_,3,6,9,_],
[3,5,2,_,1,_,_,_,6],
[_,_,_,4,5,2,3,_,_],
[_,8,1,_,3,_,2,_,_],
[6,_,3,_,4,_,8,_,9],
[5,2,_,_,_,1,_,6,_],
[_,_,_,3,_,7,_,_,_]]).
of built-in predicates that are useful for solving the Sudoku puzzle easily.
puzzle(3, [[_,5,_,1,_,_,_,_,_],
[2,_,_,5,_,_,6,_,_],
[1,_,_,_,8,_,2,_,_],
[_,8,_,4,3,_,_,_,_],
[_,_,_,_,_,_,_,4,_],
[_,_,_,_,_,7,9,3,2],
[_,4,_,6,7,_,_,_,_],
[_,7,_,_,_,_,_,1,9],
[9,_,_,_,_,8,_,_,_]]).
**(ins)/2** states the domains of variables
in some systems: fd_domain/3, domain/
**all_distinct/**
or alternatively: all_different/1, fd_all_different.
describes a list of different integers
_Examples_ :
![](sudoku-screenshots/s1.png)
Constraint Propagation:
![](sudoku-screenshots/s2.png)
# CONSISTENCY TECHNIQUES
**all_distinct/1** uses powerful methods from graph theory to prune the search space:
Using the previous example, the following graph states that X can be either 1 or 2, Y
can be either 1 or 2 and Z can be either 1, 2 or 3.
![](sudoku-screenshots/g1.png)
This is a value graph for a set of constraints.
Prolog automatically reasons about this value graph to detect whether there can still
be a solution and also to find out which assignment can not occur in a solution.
![](sudoku-screenshots/g2.png) ![](sudoku-screenshots/g3.png)
# PROGRAM
```
:- use_module(library(clpfd)). % Including clpfd library.
% Defining a sudoku latin square:
sudoku (Rows) :-
% Rows must be a list of length 9.
length (Rows, 9),
%Each of the rows must also be a list of 9.
maplist(same_length(Rows), Rows),
% The concatenation of all elements of this list is the list Vs.
append(Rows, Vs),
Vs ins 1..9,
% We can define the all the elements of each of the rows
% must be purely distinct.
% We can do the following:
% Rows = [Rs1|_], all_distinct(Rs1),
% Rows = [_,Rs2|_], all_distinct(Rs2),
% ...
% But there is a simpler way to do this.
maplist(all_distinct, Rows),
% This states that all_distinct must hold for each of the rows.
% Doing the same with columns.
transpose(Rows, Columns),
maplist(all_distinct, Columns),
% Defining the sub-squares.
Rows = [As,Bs,Cs,Ds,Es,Fs,Gs,Hs,Is],
square(As, Bs, Cs),
square(Ds, Es, Fs),
square(Gs, Hs, Is).
square([], [], []). % This predicate uses 3 rows.
square([N1,N2,N3|Ns1],
[N4,N5,N6|Ns2],
[N7,N8,N9|Ns3]) :-
all_distinct([N1,N2,N3,N4,N5,N6,N7,N8,N9]),
square(Ns1, Ns2, Ns3).
% Defining different problems.
problem(1, [[_,_,_,_,_,4,_,_,2],
[_,6,_,2,_,_,_,3,_],
[_,8,_,_,_,3,5,_,9],
[_,4,_,_,_,_,1,_,_],
[1,_,_,7,_,5,_,_,_],
[5,_,3,_,_,_,_,_,_],
[_,9,_,3,_,_,_,_,_],
[_,_,4,_,6,1,_,_,_],
[_,_,5,_,_,_,7,_,_]]).
problem(2, [[_,_,9,5,_,_,_,3,7],
[1,3,7,9,_,_,_,5,2],
[2,_,_,_,_,3,6,9,_],
[3,5,2,_,1,_,_,_,6],
[_,_,_,4,5,2,3,_,_],
[_,8,1,_,3,_,2,_,_],
[6,_,3,_,4,_,8,_,9],
[5,2,_,_,_,1,_,6,_],
[_,_,_,3,_,7,_,_,_]]).
problem(3, [[_,5,_,1,_,_,_,_,_],
[2,_,_,5,_,_,6,_,_],
[1,_,_,_,8,_,2,_,_],
[_,8,_,4,3,_,_,_,_],
[_,_,_,_,_,_,_,4,_],
[_,_,_,_,_,7,9,3,2],
[_,4,_,6,7,_,_,_,_],
[_,7,_,_,_,_,_,1,9],
[9,_,_,_,_,8,_,_,_]]).
```
# SOLUTION
We can get the solution using the following queries:
```
problem(1,Rows), sudoku(Rows), maplist(portray_clause, Rows).
```
![](sudoku-screenshots/p1.png)
```
problem(2,Rows), sudoku(Rows), maplist(portray_clause, Rows).
```
![](sudoku-screenshots/p2.png)
```
problem(3,Rows), sudoku(Rows), maplist(portray_clause, Rows).
```
# ANOTHER EXAMPLE
Following is the step by step method of how prolog solves the Sudoku puzzle using
intelligent constraint propagation.
![](sudoku-screenshots/01.png) ![](sudoku-screenshots/02.png)
![](sudoku-screenshots/03.png) ![](sudoku-screenshots/04.png)
![](sudoku-screenshots/05.png) ![](sudoku-screenshots/06.png)
Inconsistent values are indicated by small dots. Black dots represent “obvious”
propagation, whereas, blue dots represent “intelligent” propagation.
![](sudoku-screenshots/07.png) ![](sudoku-screenshots/08.png)
# REFERENCES
- https://metalevel.at/sudoku
- https://www.swi-prolog.org/man/clpfd.html

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db.pl
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@ -15,7 +15,9 @@ sudoku(Rows) :-
square(Gs, Hs, Is).
square([], [], []).
square([N1,N2,N3|Ns1], [N4,N5,N6|Ns2], [N7,N8,N9|Ns3]) :-
square([N1,N2,N3|Ns1],
[N4,N5,N6|Ns2],
[N7,N8,N9|Ns3]) :-
all_distinct([N1,N2,N3,N4,N5,N6,N7,N8,N9]),
square(Ns1, Ns2, Ns3).
@ -28,3 +30,23 @@ problem(1, [[_,_,_,_,_,4,_,_,2],
[_,9,_,3,_,_,_,_,_],
[_,_,4,_,6,1,_,_,_],
[_,_,5,_,_,_,7,_,_]]).
problem(2, [[_,_,9,5,_,_,_,3,7],
[1,3,7,9,_,_,_,5,2],
[2,_,_,_,_,3,6,9,_],
[3,5,2,_,1,_,_,_,6],
[_,_,_,4,5,2,3,_,_],
[_,8,1,_,3,_,2,_,_],
[6,_,3,_,4,_,8,_,9],
[5,2,_,_,_,1,_,6,_],
[_,_,_,3,_,7,_,_,_]]).
problem(3, [[_,5,_,1,_,_,_,_,_],
[2,_,_,5,_,_,6,_,_],
[1,_,_,_,8,_,2,_,_],
[_,8,_,4,3,_,_,_,_],
[_,_,_,_,_,_,_,4,_],
[_,_,_,_,_,7,9,3,2],
[_,4,_,6,7,_,_,_,_],
[_,7,_,_,_,_,_,1,9],
[9,_,_,_,_,8,_,_,_]]).

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